C C There are a total of 7 entries in the algebraic variable array. C There are a total of 2 entries in each of the rate and state variable arrays. C There are a total of 2 entries in the constant variable array. C C C ALGBRC(1) is V in component environment (millivolt). C VOI is t in component environment (millisec). C STATES(1) is m in component sodium_channel_m_gate (dimensionless). C STATES(2) is h in component sodium_channel_h_gate (dimensionless). C CONSTS(1) is g_Na in component sodium_channel (milliS_per_cm2). C CONSTS(2) is E_Na in component sodium_channel (millivolt). C ALGBRC(2) is Na_conductance in component sodium_channel (milliS_per_cm2). C ALGBRC(5) is i_Na in component sodium_channel (microA_per_cm2). C ALGBRC(3) is alpha_m in component sodium_channel_m_gate (per_millisec). C ALGBRC(6) is beta_m in component sodium_channel_m_gate (per_millisec). C ALGBRC(4) is alpha_h in component sodium_channel_h_gate (per_millisec). C ALGBRC(7) is beta_h in component sodium_channel_h_gate (per_millisec). C RATES(1) is d/dt m in component sodium_channel_m_gate (dimensionless). C RATES(2) is d/dt h in component sodium_channel_h_gate (dimensionless). C SUBROUTINE initConsts(CONSTS, RATES, STATES) REAL CONSTS(*), RATES(*), STATES(*) STATES(1) = 0.05 STATES(2) = 0.6 CONSTS(1) = 120 CONSTS(2) = 35 RETURN END SUBROUTINE computeRates(VOI, CONSTS, RATES, STATES, ALGBRC) REAL VOI, CONSTS(*), RATES(*), STATES(*), ALGBRC(*) ALGBRC(1) = TERNRY(VOI.GT.5.00000.AND.VOI.LT.15.0000, 0.00000, - 85.0000) ALGBRC(3) = ( - 0.100000*(ALGBRC(1)+50.0000))/(EXP(- (ALGBRC(1)+50.0000)/10.0000) - 1.00000) ALGBRC(6) = 4.00000*EXP(- (ALGBRC(1)+75.0000)/18.0000) RATES(1) = ALGBRC(3)*(1.00000 - STATES(1)) - ALGBRC(6)*STATES(1) ALGBRC(4) = 0.0700000*EXP(- (ALGBRC(1)+75.0000)/20.0000) ALGBRC(7) = 1.00000/(EXP(- (ALGBRC(1)+45.0000)/10.0000)+1.00000) RATES(2) = ALGBRC(4)*(1.00000 - STATES(2)) - ALGBRC(7)*STATES(2) RETURN END SUBROUTINE computeVariables(VOI, CONSTS, RATES, STATES, ALGBRC) REAL VOI, CONSTS(*), RATES(*), STATES(*), ALGBRC(*) ALGBRC(1) = TERNRY(VOI.GT.5.00000.AND.VOI.LT.15.0000, 0.00000, - 85.0000) ALGBRC(3) = ( - 0.100000*(ALGBRC(1)+50.0000))/(EXP(- (ALGBRC(1)+50.0000)/10.0000) - 1.00000) ALGBRC(6) = 4.00000*EXP(- (ALGBRC(1)+75.0000)/18.0000) ALGBRC(4) = 0.0700000*EXP(- (ALGBRC(1)+75.0000)/20.0000) ALGBRC(7) = 1.00000/(EXP(- (ALGBRC(1)+45.0000)/10.0000)+1.00000) ALGBRC(2) = CONSTS(1)*STATES(1) ** 3.00000*STATES(2) ALGBRC(5) = ALGBRC(2)*(ALGBRC(1) - CONSTS(2)) RETURN END REAL FUNCTION TERNRY(TEST, VALA, VALB) LOGICAL TEST REAL VALA, VALB IF (TEST) THEN TERNRY = VALA ELSE TERNRY = VALB ENDIF RETURN END